2+(x^2)/3=5x+2

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Solution for 2+(x^2)/3=5x+2 equation: 


x in (-oo:+oo)

(x^2)/3+2 = 5*x+2 // - 5*x+2

(x^2)/3-(5*x)-2+2 = 0

(x^2)/3-5*x-2+2 = 0

1/3*x^2-5*x = 0

DELTA = (-5)^2-(0*1/3*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+5)/(1/3*2) or x = (5-25^(1/2))/(1/3*2)

x = 15 or x = 0

x in { 0, 15 }

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